FileBot

Posted: **03 Nov 2015, 17:19**

Using amc -non-strict, if you change seriesFormat = {n}
to any of this, it will get the naming ok, BUT it will get wrong fanart and nfo file from different show

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tvs:   any{ seriesFormat }{ '''TV/{n.replaceFirst(/^(?i)(The|A|An)\\s(.+)/, /$2, $1/).replace(':', ' - ').trim()}/{n.replaceTrailingBrackets().trim().space('.')}{'.'+s00e00}{'.'+t.space('.').replaceAll(/[!?.]+$/).replacePart('(Part.$1)')}{'-'+group}{'.'+lang}''' },

The Avengers => Avengers, The

{n.sortName()}
{n.replaceFirst(/^(?i)(The|A|An)\s(.+)/, /$2, $1/)}

try it out with e.g. The.Librarians.S02E01

it makes a lookup only for:
http://thetvdb.com/api/GetSeries.php?se ... anguage=en

NOT
http://thetvdb.com/api/GetSeries.php?se ... anguage=en

Posted: **03 Nov 2015, 17:32**

That's why it says:

NOTE: If you mess up the filename like this, FileBot and HTPC software may have trouble making sense of the filename in the future.

You can either make sure that files are named properly, or that xattr metadata is supported and working on the relevant file system.

Posted: **03 Nov 2015, 18:07**

but its only part of it that it gets wrong

why does it lookup in 2 dif. ways ?

cant it just do the rename part last ?

or check to see if there is a ", The" ?

plus i only rename the folder NOT the file, so it still has every chance at a correct lookup

Posted: **04 Nov 2015, 01:12**

The artwork.tmdb script expects files to be organized a certain way:

Movies are expected to be organized into folders. The movie is determined using the name of the parent folder of each video file.

It also expects movies to be organized into folder, one movie per folder. FileBot has 2 different ways of doing almost everything, strict and non-strict mode that is, but once you mess with the filename things might get odd either way. I'd try removing the ", The" part at the end and see if that works better.

As I said, FileBot will *try* to store full metadata for each file in the filesystem, and it will *try* to use previously stored metadata to identify the files, so the question you should be asking is why "Why are Extended Attributes not working?".

Posted: **05 Feb 2016, 00:13**

Still using amc and xattr = OFF

In order to use:
The Avengers => Avengers, The
{n.sortName()}
{n.replaceFirst(/^(?i)(The|A|An)\s(.+)/, /$2, $1/)}

I'm trying to make a PreRename.groovy script
that looks for FOLDERS with "Avengers, The" and rename it to "The Avengers"
so I can use the amc script with e.g. {n.replaceFirst(/^(?i)(The|A|An)\s(.+)/, /$2, $1/)} again

1. Get FOLDERS ONLY (from args.getFolders() ?)
2. If e.g. "Avengers, The" rename to "The Avengers" using something like (?:(.+)(?:[,]\s)([Tt]he|[Aa]|[Aa]n)$)
3. Don't do anything to folders that have ", A" or ", An" or ", The"
4. Do this OFFLINE ONLY

Can you/anyone help pls ???

btw: i made a script that +1 the Season for American Dad! (so it match the TheTVDB season)

Code: Select all

args.getFiles{ it.isVideo() }
.each {
rename(file:it, format:"{n==~'American Dad!' ? n+' S'+(episode.season ? s+1 : 1).pad(2)+'E'+e.pad(2): fn}")
}

Posted: **05 Feb 2016, 09:43**

Rename Avengers, The to The Avengers:

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def e = /^(.+), (The|A|An)$/
def r = /$2 $1/

rename(
	map: args.getFolders().findAll{ it ==~ e }.collectEntries{ [it, it.name.replaceFirst(e, r)] }
)

Rename Alias 1x01 to Alias 2x01:

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def offset = [season: +1, episode: 0]

def p = /(\d{1,2})(\D)(\d{2})/
def r = { m, s, x, e -> ((s as int) + offset.season) + x + ((e as int) + offset.episode).pad(2) }

rename(
	map: args.getFiles().findAll{ parseEpisodeNumber(it) != null }.collectEntries{ [it, it.name.replaceFirst(p, r)] }
)

Posted: **06 Feb 2016, 02:43**

nice THX, that would have taken me weeks to do if ever

any chance to help with how to use a show filter (n==~'American Dad!') in the: ???

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def offset = [season: +1, episode: 0]

def p = /(\d{1,2})(\D)(\d{2})/
def r = { m, s, x, e -> ((s as int) + offset.season) + x + ((e as int) + offset.episode).pad(2) }

rename(
   map: args.getFiles().findAll{ parseEpisodeNumber(it) != null }.collectEntries{ [it, it.name.replaceFirst(p, r)] }
)

Posted: **06 Feb 2016, 09:40**

Something like this?

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args.getFiles().findAll{ it =~ /American.Dad/ }

Posted: **06 Feb 2016, 14:10**

thx, but I don't get where to put it in the code ?

can it take a list (if i need) ?
this the right way ?

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args.getFiles().findAll{(it =~ /(?i)American.Dad/||it =~ /(?i)Other.Show/)

EDIT: This looks like it works

Code: Select all

def offset = [season: +1, episode: 0]

def p = /(\d{1,2})(\D)(\d{2})/
def r = { m, s, x, e -> ((s as int) + offset.season) + x + ((e as int) + offset.episode).pad(2) }

rename(
map: args.getFiles().findAll{it =~ /American.Dad/ && parseEpisodeNumber(it) != null }.collectEntries{ [it, it.name.replaceFirst(p, r)] }
)

Posted: **06 Feb 2016, 15:49**

You can use any code that returns true/false as findAll{} so you can use || or but doing that in the regex right away is easier:

Code: Select all

args.getFiles().findAll{ it =~ /(?i:American.Dad|Other.Show)/ }.findAll{ parseEpisodeNumber(it) != null }

Posted: **06 Feb 2016, 16:57**

thx
btw i think i found an "error" in your script when trying to do the reverse "Rename Avengers, The to The Avengers:"

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.findAll{it ==~ e }
should be 
.findAll{it.name ==~ e }

Code: Select all

// Move The|A|An to the FRONT from the BACK
def e = /^(The|A|An)\s(.+)$/
def r = /$2, $1/

rename(
   map: args.getFolders().findAll{it.name ==~ e }.each{println "FOUND: $it.name"}.collectEntries{ [it, it.name.replaceFirst(e, r)] }
)

Posted: **06 Feb 2016, 17:09**

Good point. You'll want to do matches exactly ==~ the file.name, not the whole file path.

Posted: **13 Jun 2016, 20:29**

can you explain what makes it offline only ?

I'm trying do make this offline only:
args.getFiles{ it.isVideo() }
.each{println "FOUND: $it.name in $it.parentFile.parentFile --> $it.parentFile.parentFile.name.$it.extension"
rename(file:it, format:"{file.parentFile.parentFile}/{file.parentFile.parentFile.name}")
}

this almost works (move 1 dir up part missing):
def String input = ''
def String output = ''

rename(map: args.getFiles{ it.isVideo() }
.each{input=it.name; println "FOUND: $it.name in $it.parentFile.parentFile --> $it.parentFile.parentFile.name.$it.extension"
output = it.parentFile.parentFile.name+'.'+it.extension
}
.collectEntries{ [it, it.name.replaceFirst(input, output)] }
)

Posted: **13 Jun 2016, 21:21**

You can pass in a File->File map: rename(map: Map<File,File>)

But if you really just want to move/rename files then you can just do it directly File.renameTo(File) without any of the FileBot-specific APIs.

Posted: **16 Jun 2016, 13:53**

1. if this "You can pass in a File->File map: rename(map: Map<File,File>)"
answers "can you explain what makes it offline only"...

then I don't get it... can you dumb it down, pls ?

2. don't think I can use "File.renameTo(File)"
I need the ".isVideo()" part

3. Is there a way I can use the GUI to test script proper without F*ing it up like this:
"{def String input = ''; def String output = ''; file.getFiles{ it.isVideo() }.each{input=it.name; output = it.parentFile.parentFile.name+'.'+it.extension }.collectEntries{ [it, it.name.replaceFirst(input, output)] } }"

Posted: **16 Jun 2016, 14:24**

1.
If you pass in a map of files, then it will just rename files accordingly. There will be no online lookups of any kind.

2.
Does one have anything to do with the other?

3.
Press F5 to open the Groovy pad. Also, why would you not use newlines? It's quite unreadable. I'm not sure what it's supposed to do, but I'm sure there's a more elegant solution.

PS: I'm talking about Groovy scripting. I'm not talking about FileBot format expressions. In case there's a confusion here.

EDIT:

If this is a one-off problem, then I'd just do it with the GUI:
viewtopic.php?f=3&t=2072

Posted: **16 Jun 2016, 19:30**

I have seen "Groovy pad" before, but ever used, because I don't know how to ?

If I try to run e.g.
args.getFiles{ it.isVideo() }
.each{println "FOUND: $it.name in $it.parentFile.parentFile --> $it.parentFile.parentFile.name.$it.extension"
rename(file:it, format:"{file.parentFile.parentFile}/{file.parentFile.parentFile.name}")
}

I get only "Result: []"

how to pass args to it ?
file = No such property: file for class: Script57
and so on... ?
it's like it has nothing to do with filebot, only "vanilla" groovy/java code ?

I need a visual way to show instant results in order to make scripts via the "trial and error" way (my way)

Posted: **17 Jun 2016, 05:06**

Step 1:

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println args

Result: Oh, it's empty by default because I'm not using the command-line to pass in arguments.

Step 2:

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def args = ['/path/to/folder' as File]
println args

Result: Ok, not empty anymore!

Step 3:

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def args = ['/path/to/folder' as File]
args.getFiles{ it.isVideo() }.each{
	println it
}

Result: Ok, selecting video files works.

I'll leave the rest up to you.

FileBot

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