FileBot

since the changes i now use

{n.take(40)} - {s.pad(2)+'x'}{e.pad(2)}{' Special '+special.pad(2)} - {t.take(40)} - [{any{group}{'NoGroup'}}] {source} [{resolution}] {video.codecID.join('-').replace('/', ' ')} {[vc, VF, af]} [{video.bitdepth.join('-')} {'Bit'}] {[audio.language].findAll{[null] != it}.join (", ")}​{'; ' +[text.language.join (", ")]}
due to Rednoahs help

For most of it It works like a charm
Giving something like:
Series - 11x01 - Episode - [NoGroup] HDTV [720x404] avc1 [x264, 480p, 2ch] [8 Bit] [8 Bit] [en, es]​; [en].mp4

And sometimes i get funy results like
series- 036 - episode - [[NoGroup] [640x480] XVID [XviD, 480p, 2ch] [8 Bit] [Undefined]​.avi

It seems some ppl Put "Undefined" or [Undefined]" in to an undefined Filed...

I tried Now to filter them Out adding || and && clauses or cascading to the {[audio.language].findAll{[null] != it}.join (", ") but i am not versed enough To make it work - most times it dosent give out anything anymore as subtitle Information

The null or undefined Filter may also be needed with the Bit part and the subtitles but baby steps
did someone have that fun already?
i didnt find it in the forum

anny tipp would be appreciated

e.g. remove null / Undefined:

{(audio.language.findAll() - [null] - ['Undefined'] - ['[Undefined]'].join(", "))}


That above seems working but Leaves again [] the moment t had to remove something of the undesired values

i did not get any working audio languages list as i trid To put all in one list to remove like [null, 'Undefined']

is there a way to define the output a string and use replace on that?

Mind your parentheses:

Thanks; i Git the substractions at once now running

{n.take(40)} - {s.pad(2)+'x'}{e.pad(2)}{' Special '+special.pad(2)} - {t.take(40)} - [{any{group}{'NoGroup'}}] {source} [{resolution}] {video.codecID.join('-').replace('/', ' ')} {[vc, VF, af]} [{video.bitdepth.join('-') - null}{' Bit'}] {'[' + {(audio.language - [null, 'Undefined']).join(', ')} + ']'}{'; ' +[(text.language - [null, 'Undefined']).join(', ')]}

Or

{n.take(40)} - {s.pad(2)+'x'}{e.pad(2)}{' Special '+special.pad(2)} - {t.take(40)} - [{any{group}{'NoGroup'}}] {source} [{resolution}] {video.codecID.join('-').replace('/', ' ')} {[vc, VF, af]} [{video.bitdepth.join('-') - null}{' Bit'}] [{(audio.language - [null, 'Undefined']).join(', ')}]{'; ' +[(text.language - [null, 'Undefined']).join(', ')]}


I tried different wasys But each time if there WAS something to take out of the listing I get []
Like ,,,[640x480] XVID [XviD, 480p, 2ch] [8 Bit] [] ​.avi

Its like an empty list is still a true for the Filter Purposses

someone in the Spork release group found it necessary to put 'Undefined / ja' in audio.language
I put that one inthe filter too but is there a Way to say " look over all and take Out all /?

Something like this? Just drop everything that doesn't look like a language code:

Learn how {expressions} work and useful Helper Functions