FileBot

Posted: **21 Jul 2013, 14:32**

Hi, I wanted to have something like this:

{n} ({y})/{filename}

The closest I could find was {file} which contains the fullpath.

Any way of having the original filename in the renaming scheme?

Thanks

Posted: **21 Jul 2013, 15:38**

You mean {fn} which is the filename without extension? Or {file.name} which is the filename?

Posted: **21 Jul 2013, 15:49**

file.name is exactly what I was looking for, thanks!

Renaming scheme original filename?