Hi,

is it possible to only return Audio Codec from specified Audio Language?

For example like:

If audio.language = 'de' then return audio.codec

Hope someone has an solution

Thank you

You broke the expression. Here I fixed it:
{audios.collect{ a -> allOf{[any{a.CodecIDHint}{a.Codec}, a.Channels+'ch']}{a.Language} }.findAll{ it[1] }.groupBy{ it[0] }.collect{ k, v -> k + v*.get(1) }.flatten().join('.') }

See how the groupBy key is a Array of Codec/Channels. :ugeek:

That's it ...

any{a.CodecIDHint}{a.Codec}

I tried this:
{audios.collect{ a -> allOf{any{a.CodecIDHint}{a.Codec}}{a.Language} }.findAll{ it[1] }.groupBy{ it[0] }.collect{ k, v -> k + v*.get(1) }.flatten().join('.') }
but get no value (just blank).

I also tried:
{audios.collect{ a -> allOf{[{if (a ...

This is how I'd write that:
{audios.collect{ a -> allOf{[a.codec, a.channels+'ch']}{a.Language} }.findAll{ it[1] }.groupBy{ it[0] }.collect{ k, v -> k + v*.get(1) }.flatten().join('.') }

If you use a binding that is undefined/null/etc it'll cause an Exception to be thrown. So you can catch that ...

Wow thank you very much! Works like charm

Hi,

I'd like to read out all Audio Informations, which is working great with most of my files.
This is my scheme:

{'.' + audios.groupBy{ it.Codec + '.' + it.Channels.replaceAll(/[' ']/, "-") + 'ch' }.collect{ c, a -> [c] + a*.Language }.flatten().join('.')}

The problem is, if files doesn't ...