
Thanks!!!
And thanks for the testing licence, too!
Got it,rednoah wrote: ↑30 Nov 2024, 09:43 e.g.Format: Select all
{ n } - { s00e00 } - { t } - { episode.info.cast.name.join(', ') } ({ airdate.year })
That's much easier to understand!rednoah wrote: ↑29 Feb 2024, 12:47 The simple version will look more like this:Format: Select all
{ (n + ' - ' + s00e00 + ' - ' + t).replace('<':'﹤','>':'﹥',':':'꞉','"':'“','/':'⁄','|':'⼁','?':'?','*':'﹡','\\':'∖') }