Identify files with no subtitles

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ca81
Posts: 18
Joined: 14 Dec 2019, 20:08

Identify files with no subtitles

Post by ca81 »

Hi,

Going through various posts in the forum and some Q&A, I have put together the below code:

Code: Select all

({text.size() >=1 ? 
{text.take(2).collect
	{ a -> allOf
	{ any{a.Language_String3.upper()} {'XSX'} }
	{ a.Format.replace('-':'') }
	}*.joining('-').join(', ')
}: 'No Subs'})
My intention from this piece of code is for it to display,
  • info about only the first two subtitles,
  • No subs when there are no subtitles and
  • XSX when the language of the subtitle is not defined
the above code works fine as long there are 1 or more subtitles but if the media file does not have subtitles then I don't get No subs as the output :(.

Any help is greatly appreciated...

thanks,
~kg
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rednoah
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Posts: 18841
Joined: 16 Nov 2011, 08:59
Location: Taipei
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Re: Identify files with no subtitles

Post by rednoah »

If you use text on a file that does not contain any text streams, then the result will not be an empty list, but a binding error that unwinds the expression"
viewtopic.php?t=1895


So we use any to catch that error and print something else instead:

Code: Select all

{
	any{ text.take(2).collect{ a ->
		allOf
			{ any{ a.LanguageString3 }{ 'XSX' }.upper() }
			{ a.Format.removeAll('-') }
			.join('-')
		}.join(', ')
	}{ 'No Subtitles' }
}
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ca81
Posts: 18
Joined: 14 Dec 2019, 20:08

Re: Identify files with no subtitles

Post by ca81 »

rednoah wrote: 11 Sep 2020, 08:01 So we use any to catch that error and print something else instead:

Code: Select all

{
 any{ text.take(2).collect{ a ->
 allOf
 { any{ a.LanguageString3 }{ 'XSX' }.upper() }
 { a.Format.removeAll('-') }
 .join('-')
 }.join(', ')
 }{ 'No Subtitles' }
}
Thanks!!!, this works perfectly :)

rednoah wrote: 11 Sep 2020, 08:01 If you use text on a file that does not contain any text streams, then the result will not be an empty list, but a binding error that unwinds the expression"
viewtopic.php?t=1895
I kinda realized the above when I was trying to resolve my issue and wrote the below piece of code.

Code: Select all

{{any{text.size} {0}} >=1 ? 
{text.take(2).collect
	{ a -> allOf
	{ any{a.Language_String3.upper()} {'XSX'} }
	{ a.Format.replace('-':'') }
	}*.joining('-').join(', ')
}: 'No Subs'}
My code snippet above does not work as intended and just for my understanding/learning can someone please advise on what's wrong here?
I am using FileBot GUI and the format editor gives the following error with my code snippet above.
https://imgur.com/8OoUU64
...this again I am unable to understand due to my non-coding background :(

Please advise.

thanks,
~kg

ps: for some inexplicable reason when I put the error that I was getting in FileBot as a text in this response, I kept on getting an 'Internal Server Error' on the website each time I 'previewed' the response. So finally decided to make an image of the error text and post it's url
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rednoah
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Posts: 18841
Joined: 16 Nov 2011, 08:59
Location: Taipei
Contact:

Re: Identify files with no subtitles

Post by rednoah »

The outer-most {...} delimitate Groovy code. But Groovy itself uses {...} for code blocks and closures, so inner {...} have completely different semantics compared to the outer-most {...}. Notably, {...} is not used to reference variables, it's used to delimitate Groovy code sections of arbitrary length. It just so happens that simple code like vc is valid Groovy code, making {vc} valid FileBot Format code.


e.g. Groovy code

Code: Select all

// assign "Integer 1" to variable x
def x = 1
// assign "Closure that returns Integer 1 when called" to variable y
def y = { 1 }
:arrow: https://groovy-lang.org/closures.html
:idea: Please read the FAQ and How to Request Help.
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