let filebot choose genre from a list

[Mendeln]

hi

first thinks first, thank you very much for this wonderful program rednoah

im quite happy with my expression, especially the collection handling
thanks to the forum and many many hours of reading and trail and error i came up with this:

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I:/{any{readLines('H:/Filmdatenbank/Filmreihe.txt').find{ it =~ imdbid }.after(':')}{any{model.findAll{ it.collection == collection }.genres.flatten().countBy{it}.sort{it.value}.keySet().first()}{genres[0]}}}/{n.replaceAll(/[`´‘’“”""]/, "'").replace(/:/, " - ").replace(/·/, "-").replaceAll(/[½]/, " 1'2").replaceAll(/[⅓]/, " 1'3").replace(/ß/,"ss").replace(/ä/,"ae").replace(/ö/,"oe").replace(/ü/,"ue")} ({y}) [{vf}] [{ac} {af.replace('8ch',' 7.2').replace('7ch',' 6.1').replace('6ch',' 5.1').replace('3', ' 2.1').replace('3ch',' 2.1').replace('2ch',' Stereo')}] [{genres.take(3).join(', ').replaceAll(/ä/,"ae").replaceAll(/ö/,"oe").replaceAll(/ü/,"ue")}]

Filmreihe.txt

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StarTrek
tt0079945;tt0111280;tt0253754;tt0796366;tt1408101;tt2660888;tt0092007;tt0098382;tt0102975;tt0117731;tt0120844;tt0084726;tt0088170:Science Fiction

Insidious
tt1591095;tt2226417;tt3195644:Horror

Pippi Langstrumpf
tt0066265;tt0066227;tt0366905;tt0093744:Familie

X-Men mit Wolverine und Deadpool
tt0120903;tt3385516;tt0376994;tt1270798;tt1877832;tt0290334;tt0458525;tt1431045:Abenteuer

Sissi
tt0048624;tt0049762;tt0050974:Drama

Harry Potter
tt0330373;tt0304141;tt0417741;tt0373889;tt0241527;tt0926084;tt1201607;tt0295297:Familie

Alien
tt0078748;tt0090605;tt0103644;tt0118583:Horror

Matrix
tt0133093;tt0234215;tt0242653:Action

but i have too many genres... i dont want Foreign, Abenteuer, Historie, Musik, Western or Animation
is there a way to let filebot choose the best genre from a list?
in my case there would only be Action, Drama, Familie, Fantasy, Horror, Komödie, Lovestory, Mystery, Science Fiction and Thriller.

im using v4.7.2 r4178 win7

[rednoah]

1.
If you have lots of replace-repetition, you can just pass in a map of replacements:

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{'äiüeö'.replace([ä:'a', ü:'u', ö:'o'])}

And those replacement mappings could be encapsulated in an external csv file:

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{'äiüeö'.replace(csv("$HOME/aiueo.csv"))}

2.
You can sort {genres} any way you want (e.g. by using your own value/order map).

e.g. sample code

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{def order = [A:1, B:2, C:3, D:4].withDefault{ 100 }; ['D', 'C', 'K', 'X', 'B', 'A'].sort{ order[it] } }

Please use an external csv file for your Value->Priority mappings.


Once you have a list of genres sorted by your preferred priority order, then you can just take the Top N items:

e.g. take the first 3 genres (without any custom sort)

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{genres.take(3)}

[Mendeln]

i use this expression for science

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{def order = [Horror:1, Action:2, 'Science Fiction':3, Fantasy:4, Komödie:5, Drama:6, Lovestory:7, Mystery:8, Familie:9, Thriller:10, Abenteuer:11, Animation:12, Foreign:13, Historie:14, Musik:15, Western:16].withDefault{ 100 }; genres.take(1).sort{ order[it] } } {n}

but it will only sort the genres if write: genres.take(2)

and how do i combine this to let it work with my actual "in use" expression?

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{any{readLines('H:/Filmdatenbank/Filmreihe.txt').find{ it =~ imdbid }.after(':')}{any{model.findAll{ it.collection == collection }.genres.flatten().countBy{it}.sort{it.value}.keySet().first()}{genres[0]}}}

[rednoah]

So you reduce the list to one 1 single item first and then you sort the result?

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genres.take(1).sort{ order[it] } }

Taking the first item AFTER sorting them probably makes more sense.

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genres.sort{ order[it] }.take(1)

If you just want the first item, then this will be easier:

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genres.max{ order[it] }